php 实现收藏功能的示例代码

整理文档，搜刮出一个php 实现收藏功能的示例代码，稍微整理精简一下做下分享。

HTML:

<a class = "x" id="{$photo.id}" uid="{$Think.session.uid}" status = "{$collect_pic}" href = "javascript:void(0);">
<if condition = "$collect_num gt 0">
  <span>取消收藏</span>
<else/><span>收藏</span></if></a>

Js:

//点击收藏，实现已收藏
  $(".x").on("click",function(){
    var Oa=$(this);
    var id=Oa.attr("id");//获取图片id属性
    var uid = Oa.attr("uid");//获取用户id
    var status = Oa.attr("status"); //获取收藏状态 1收藏，0取消收藏
    $.post("url",{id:id,uid:uid,status:status},function(msg){
      if(msg.status==1){
        Oa.find("span").text("取消收藏");
        Oa.attr("status","1");
      }else{
        Oa.find("span").text("收藏");
        Oa.attr("status","0");
      }
    },"json")
  })

PHP:

//判断用户是否已收藏该图片
      $data["uid"] = $_SESSION["uid"];
      $data["pid"] = $pid;
      $collect_pic = M("collect")->where($data)->getfield("status");
      $this->collect_num = $collect_num;
      $this->collect_pic = $collect_pic;

//收藏成功
    public function cang(){

      $data["pid"] = isset($_POST["id"])?intval(trim($_POST["id"])):0;
      $data["uid"] = $_SESSION["uid"];
      //默认o收藏 1取消收藏
      $status = isset($_POST["status"])?intval(trim($_POST["status"])):0;
      $db = M("collect");
      if($status == 0){
        //数据组装，忽略
        if(M("collect")->data($collect)->add()){
          $msg["info"] = "ok";
          $msg["status"] = 1;
          $this->ajaxreturn($msg);
          exit;        
        }else{
          $msg["info"] = "fail";
          $msg["status"] = 1;
          $this->ajaxreturn($msg);
        }
      }else{
        //取消收藏
        if($db->where($data)->delete()){
          $msg["info"] = "ok";
          $msg["status"] = 0;
          $this->ajaxreturn($msg);
          exit;
        }else{
          $msg["info"] = "fail";
          $msg["status"] = 0;
          $this->ajaxreturn($msg);
        }
      }

思路：基本没什么难度，注意细节即可。

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